I want to display the first 110 characters of a database entry. Pretty easy so far:
我想显示数据库条目的前110个字符。很简单:
<?php echo substr($row_get_Business['business_description'],0,110) . "..."; ?>
But the above entry has html code in it that's been entered by the client. So it displays:
但是上面的条目中有客户机输入的html代码。所以它显示:
<p class="Body1"><strong><span style="text-decoration: underline;">Ref no:</span></strong> 30001<strong></stro...
Obviously no good.
显然不行。
I just want to strip out all html code, so I need to remove everything between < and > from the db entry THEN display the first 100 chars.
我只想去掉所有的html代码,因此需要从db条目中删除 <和> 之间的所有内容,然后显示前100个字符。 和>
Any ideas anyone?
有什么想法吗?
99
use strip_tags
使用strip_tags
$text = '<p>Test paragraph.</p><!-- Comment --> <a href="#fragment">Other text</a>';
echo strip_tags($text); //output Test paragraph. Other text
<?php echo substr(strip_tags($row_get_Business['business_description']),0,110) . "..."; ?>
15
Use PHP's strip_tags() function.
使用PHP的strip_tags()函数。
For example:
例如:
$businessDesc = strip_tags($row_get_Business['business_description']);
$businessDesc = substr($businessDesc, 0, 110);
print($businessDesc);
9
Let say you have string contains anchor tag and you want to remove this tag with content then this method will helpful.
假设你有一个包含锚标记的字符串,你想要删除这个带有内容的标签,那么这个方法会很有用。
$srting = '<a title="" href="/index.html"><b>Some Text</b></a>
Lorem Ipsum is simply dummy text of the printing and typesetting industry.';
echo strip_tags_content($srting);
function strip_tags_content($text) {
return preg_replace('@<(\w+)\b.*?>.*?</\1>@si', '', $text);
}
Output:
输出:
Lorem Ipsum is simply dummy text of the printing and typesetting industry.
Lorem Ipsum只是印刷业和排字业的虚拟文本。
5
use this regex: /<[^<]+?>/g
使用这个正则表达式:/ <[^ <]+ ? > / g
$val = preg_replace('/<[^<]+?>/g', ' ', $row_get_Business['business_description']);
$businessDesc = substr(val,0,110);
from your example should stay: Ref no: 30001
从您的示例中应该保留:Ref no: 30001
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