如何获取包含特定搜索字符串的文件名及其句子的列表?
[英]How to get list of file names and their sentence containing a specific search string?
I tried with following command on unix machine:
我在unix机器上尝试了以下命令:
ls -l | awk '{print $9}' | xargs -I {} cat {} | grep {"String to search"}
Though this works with text files but when i try it with xml files it is not able to display proper grepped text.Instead it displays whole xml file.
虽然这适用于文本文件，但是当我尝试使用xml文件时，它不能显示正确的加了油的文本。相反，它显示整个xml文件。
I think the possible reason behind this is absense of new line character in xml file that i use.
我认为这背后可能的原因是我使用的xml文件中没有新的行字符。
Example: Search string: "/1031/"
示例:搜索字符串:/ 1031 /
Xml line containing search string: <eventtype uri="{any_url}/1031/"/>
包含搜索字符串的Xml行:
To clarify a bit :
澄清一点:
ls -l | awk '{print $9}' | xargs -I {} cat {} | grep -o "/1031"
ls -l | awk '{打印$9}' | xargs -I {} | grep -o "/1031"
This gives output as:
这使输出为:
/1031
/ 1031
/1031
/ 1031
/1031...
/ 1031…
I also want the name of the file in which it belongs.
我还需要它所属的文件的名称。
2 个解决方案
#1
4
grep has a flag -o which only outputs the matching text.
grep有一个标记-o，它只输出匹配的文本。
ls -l | awk '{print $9}' | xargs -I {} cat {} | grep -o {"String to search"}
From your edit it looks like you need the "line" that contains the URL as well. By default grep will match greedily which means a regex to account for the XML formatting will still give you an incorrect result.
从您的编辑中，看起来您还需要包含URL的“行”。默认情况下，grep将贪婪地匹配，这意味着用于解释XML格式的regex仍然会给出错误的结果。
I can think of 2 possible options:
我可以想到两种可能的选择:
For the next examples, test.xml contains the string:
对于下一个示例，测试。xml包含字符串:
<eventtype uri="{www.example1.com}/1031/"/><eventtype uri="{www.example2.com}/1031/"/><eventtype uri="{www.example3.com}/1031/"/>
The first is to use the -P flag for grep to enable perl syntax and match lazily.
第一个是使用grep的-P标志来启用perl语法并延迟匹配。
grep -Po '".*?/1031/"' test.xml
This outputs:
这个输出:
"{www.example1.com}/1031/"
"{www.example2.com}/1031/"
"{www.example3.com}/1031/"
The second is to use sed to manually append a newline after each match and pipe to grep:
第二是使用sed在每次匹配后手动添加新行，并将管道连接到grep:
sed 's/1031/1031\n/g' test.xml | grep 1031
Outputs:
输出:
<eventtype uri="{www.example1.com}/1031
/"/><eventtype uri="{www.example2.com}/1031
/"/><eventtype uri="{www.example3.com}/1031
I believe both methods should work ok on plain text files although you may need to conditionally use one of these methods on .xml extensions.
我认为这两种方法在纯文本文件上都可以工作，尽管您可能需要在.xml扩展上有条件地使用其中的一种方法。
#2
1
Dear You could use below command
亲爱的你可以使用下面的命令
find -type f -exec grep -HPo '".*?/1031/"' {} \;
Sample Output
样例输出
[root@MUM03S001 ~]# find -type f -exec grep -HPo '".*?/1031/"' {} \;
[root@MUM03S001 ~]#查找-type f -exec grep -HPo '" *?/ 1031 /“{ } \;
./File:"{www.example1.com}/1031/"
/文件:“{ www.example1.com } / 1031 /”
./File:"{www.example2.com}/1031/"
/文件:“{ www.example2.com } / 1031 /”
./File:"{www.example3.com}/1031/"
/文件:“{ www.example3.com } / 1031 /”
[root@MUM03S001 ~]#
root@MUM03S001 ~ #
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