提取基于模式的数组中定义的字符串变量
[英]extract string variables defined in an array based on pattern
Special parameter "$@" contains the following string variables,
特殊参数“$ @”包含以下字符串变量，
echo $@ outputs: a.bdf, b.bdf,c.nas,d.nas
echo $ @ outputs：a.bdf，b.bdf，c.nas，d.nas
I want to extract the string variables with extension 'bdf' and save it in another array. Is it possible to do so in bash?
我想用扩展名'bdf'提取字符串变量并将其保存在另一个数组中。是否有可能在bash中这样做？
3 个解决方案
#1
1
Just iterate through it with a for loop :
只需使用for循环遍历它：
for ARG in "$@";do
if [[ "$ARG" == *.bdf ]];then
BDF_ARRAY+=("$ARG") #you don't need to initialize this array before the loop in bash
else #optional block, if you want to split $@ in 2 arrays
OTHER_ARRAY+=("$ARG")
fi
done
echo ${BDF_ARRAY[@]}
echo ${OTHER_ARRAY[@]}
#2
0
Using for loop
使用for循环
for i in "$@";do
if [[ "${i##*.}" == bdf ]]; then
ARRAY2+=("$i")
fi
done
#3
0
In the generic case:
在一般情况下：
#!/bin/bash
for i in "$@"; do
case "$i" in
*.bdf) BDF_ARRAY+=("$i")
;;
*.nas) NAS_ARRAY+=("$i")
;;
esac
done
for i in "${BDF_ARRAY[@]}"; do echo "BDF: $i"; done
for i in "${NAS_ARRAY[@]}"; do echo "NAS: $i"; done
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