I have the following code to get selected columns in Django
我有以下代码来获取Django中的选定列
>>> l = Listing.objects.values("id", "City")[:10]
>>> l
[{'City': u'GLENN DALE', 'id': 1459}, {'City': u'SHADY SIDE', 'id': 1460}, {'City': u'BALTIMORE', 'id': 1474}, {'City': u'BALTIMORE', 'id': 1463}, {'City': u'EDGEWOOD', 'id': 1464}, {'City': u'CAPITOL HEIGHTS', 'id': 1466}, {'City': u'ROCK HALL', 'id': 1465}, {'City': u'RIVA', 'id': 1468}, {'City': u'PRINCE FREDERICK', 'id': 1469}, {'City': u'FREDERICK', 'id': 1470}]
>>>
If I pass the "l" object to the template, I will have a list of dictionary. However, I have a function that's attached to the Listing model, and need it call it from the template.
如果我将“l”对象传递给模板,我将有一个字典列表。但是,我有一个附加到Listing模型的函数,需要它从模板中调用它。
The following will output nothing, how do I get back to the object?
以下将不输出任何内容,如何返回对象?
{% for obj in l %}
{{obj.get_images}}
{% endfor %}
1
Try using only
instead of values
like:
请尝试仅使用以下值:
l = Listing.objects.only("id", "City")[:10]
Get more info about only
here
仅在此处获取更多信息
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